A blog for medical students to practice multiple choice questions for FCPS part one, MRCP, USMLE, PLAB and lot of articles.
Site Navigation
▼
Monday, 31 March 2014
Saturday, 29 March 2014
FCPS part 1 Medicine solved mcqs with explanation Q13
Q13: ECG of a patient shows
progressively increasing PR intervals followed by dropped beat. What is the
condition?
a) Third degree heart block
b) Mobitz Type 1
c) Sinus arrhythmia
d) Mobitz Type 2
Correct Answer: b
Explanation:
Heart blocks are of three types:
- First degree heart block: PR interval prolonged (>200 ms)
- Second degree heart block:
- Mobitz Type 1: Progressive lengthening of the PR interval until a beat is dropped (a P wave not followed by a QRS complex).
- Mobitz Type 2: Dropped beats that are not preceded by a change in the length of the PR interval
FCPS part 1 Medicine solved mcqs with explanation Q12
Q12: A woman living at a hill
station has had an uncomplicated pregnancy. She is brought to the hospital at
the onset of labour. An ultrasound scan is performed which shows no fetal
abnormality. The baby can still have which of the following conditions?
a) Transposition of great vessles
b) Patent ductus arteriosis
c) Limb defects
d) Tetrology of Fallot
Correct Answer: b
Explanation:
During fetal period, the ductus
arteriosus shunts blood from the right to the left. It connects the pulmonary
trunk with the aorta. Blood entering the pulmonary trunk from the right
ventricle is shunted through ductus arteriosus into aorta. As the baby is born,
the circulatory changes that occur also include closure of the ductus
arteriosus. Closure of the ductus arteriosus is promoted by increase oxygen
tension (when baby starts breathing) which decrease prostaglandin (PG)
synthesis. At hill stations, the atmospheric oxygen pressure is low. A baby
born and staying during the first few days of his life under such circumstances
would lead to a decrease in oxygen tension and so failure of ductus arteriosus
to close. Patency of ductus arteriosus can also be maintained by high PG levels
such with use of indomethacin (a PG synthesis inhibitor). In summary low oxygen
tension and high PG levels cause PDA.
Friday, 28 March 2014
FCPS part 1 Medicine solved mcqs with explanation Q11
Q11: Which of the followings is
increased in first response?
a) IgM
b) IgD
c) IgE
d) IgG
Correct Answer: a
Explanation:
IgM is the antibody produced in
primary response to an antigen. IgG is the main antibody in secondary response.
IgM also fixes complement but does not cross placenta.
FCPS part 1 Medicine solved mcqs with explanation Q10
Q10: Which of the followings cross
placenta?
a) IgM
b) IgA
c) IgG
d) IgD
Correct Answer: c
Explanation:
Of all the immunoglobins only IgG is
the only antibody that crosses placenta. It is main antibody in secondary
response and the most abundant one. It fixes complement, opsonized bacteria,
neutralizes bacterial toxins and viruses.
FCPS part 1 Medicine solved mcqs with explanation Q9
Q9: Gastroesophageal junction
competence is increased by:
a) Lying supine
b) Paralysis of the diaphragm
c) Use of Morphine
d) Use of Metoclopromide
e) Increased intra-abdominal
pressure
Correct Answer: d
Explanation:
Metoclopromide is D2 receptor
antagonist that increased the resting tone of GIT, increases contractility
& increases Lower esophageal junction tone. It is clinically used
for Diabetic & post-surgery gastroparesis. Toxicity includes parkinsonian
effects, restlessness, drowsiness, fatigue, depression, nausea, diarrhea.
Contraindicated in patients with small bowel obstruction.
Other option under this question
actually decrease the GE junction tone.